How many grams of cacl2 are present in 25ml of a 0.500m solution?

The grams of cacl2 are presented in 25 ml of a 0.500 M solution is calculated as follows

find the number of moles

moles = molarity x volume/1000

= 0.500 x25 / 1000 = 0.0125 moles

mass = moles x molar mass of cacl2

= 0.0125 mol x 111.1 g/mol = 1.389 grams