Ask Question
3 October, 20:30

A gas is contained in a thick-walled

balloon. When the pressure changes

from 18.7 psi to 20.2 psi, the volume

changes from 0.475 L to 1.054 L and

the temperature changes from

K to 465 K.

+3
Answers (1)
  1. 3 October, 23:55
    0
    T₁ = 194 K

    Solution:

    Data Given:

    Initial Temperature = T₁ = ?

    Final Temperature = T₂ = 465 K

    Initial Pressure = P₁ = 18.7 psi

    Final Pressure = P₂ = 20.2 psi

    Initial Volume = V₁ = 0.475 L

    Final Volume = V₂ = 1.054 L

    Formula Used:

    Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

    P V = n R T

    where; R = Universal Gas Constant = 0.082057 atm. L. mol⁻¹. K⁻¹,

    Taking number of moles and R constant we can have following formula for initial and final states,

    P₁ V₁ / T₁ = P₂ V₂ / T₂

    Solving for T₁,

    T₁ = P₁ V₁ T₂ / P₂ V₂

    Putting values,

    T₁ = (18.7 psi * 0.475 L * 465 K) / (20.2 psi * 1.054 L)

    T₁ = 194 K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A gas is contained in a thick-walled balloon. When the pressure changes from 18.7 psi to 20.2 psi, the volume changes from 0.475 L to 1.054 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers