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5 August, 04:05

How much water must be added to 36.0 g of srcl2 to produce a solution that is 35.0 wt% srcl2? how much water must be added to 36.0 of to produce a solution that is 35.0 wt%? 48.6 g 66.9 g 103 g 97.2 g?

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  1. 5 August, 05:11
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    To solve this problem we will use the following equation:

    w = (m of solute) / (m of solution)

    w - percentage

    It is necessary to mention here that mass of solution is a sum of the mass of solute and mass of water.

    w = mass CaCl2 / (mass of water + mass of CaCl2)

    mass of water = x

    0.35 = 36 / (x + 36)

    0.35 * (x + 36) = 36

    0.35x + 12.6 = 36

    0.35x = 23.4

    x = 66.86 g of water is necessary
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