Ask Question
5 August, 04:06

In an attempt to prepare n-propylbenzene, a chemist alkylated benzene with 1-chloropropane and aluminum chloride. However, two isomeric hydrocarbons were obtained in a ratio of 2:1, the desired n-propylbenzene being the minor component. What do you think was the major product? How did it arise?

+1
Answers (2)
  1. 5 August, 05:01
    0
    From the given problem statement, he was attempting to prepare n-propylbenzene by alkylation benzene with 1-chloropropane and aluminum chloride, but 1-propyle benze was a major product in result.
  2. 5 August, 05:51
    0
    2-Phenylpropane (Cumene)

    Explanation:

    Famous Friedel Craft Alkylation.

    Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.

    AlCl3 + CH3CH2CH2Cl - -> AlCl4 - + CH3CH2CH2+

    CH3CH2CH2 + - --> CH3CH (+) CH3

    C6H6 + CH3CH (+) CH3 - --> C6H5CH (CH3) 2 + H+

    AlCl4 - + H + - --> HCl + AlCl3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “In an attempt to prepare n-propylbenzene, a chemist alkylated benzene with 1-chloropropane and aluminum chloride. However, two isomeric ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers