For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.4310-4 / s and the rate constant at 666 K is 8.2810-3 / s. The activation energy for the gas phase decomposition of 1-bromopropane is

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Chemistry

Janiyah Hancock

24 November, 06:03

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.4310-4 / s and the rate constant at 666 K is 8.2810-3 / s. The activation energy for the gas phase decomposition of 1-bromopropane is

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Iliana Price · Answer 1

Answer is: activation energy of this reaction is 212,01975 kJ/mol.

Arrhenius equation: ln (k ₁/k₂) = Ea/R (1/T₂ - 1/T₁).

k ₁ = 0,000643 1/s.

k ₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁ = 1/622 K = 0,0016 1/K.

1/T ₂ = 1/666 K = 0,0015 1/K.

ln (0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).

-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).

Ea = 212019,75 J/mol = 212,01975 kJ/mol.

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43*10-4 / s and the rate constant at 666 K is 8.28*10-3 / s. The activation energy for the gas phase decomposition of 1-bromopropane is

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.4310-4 / s and the rate constant at 666 K is 8.2810-3 / s. The activation energy for the gas phase decomposition of 1-bromopropane is