How many grams are in 1.68 x 1026 molecules of CO2? (molar mass=44.01 g/mol) (Hint: You will need to use your entire stoichiometry flow chart)

According to Avogadro's law 1 mole contains 6.022 * 10^23 particles

1 mole of carbon = 44.01 g / mol

Therefore;

44.01 g = 6.022 * 10^23 molecules

Hence, 1.68*10^26 molecules will have a mass of;

(44.01 * 1.68*0^26) / 6.022*10^23

= 1.228 * 10^4 molecules