At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at - 20.0 o C?

The temperature that would the volume of a gas be 0.550l if it had a volume of 0.432 L at - 20.0 c is calculated using the Charles law formula

that is v1/T1=V2/T2

V1=0.550 l

t1=?

T2 = - 20 c + 273 = 253 K

v2 = 0.432 l

by making T1 the subject of the formula T1 = V1T2/V2

T1 = (0.55lL x253) / 0.432 l = 322.11 K or 322.11-273 = 49.11 C