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22 June, 10:13

Express the concentration of a 0.0610 m aqueous solution of fluoride, f-, in mass percentage and in parts per million. assume the density of the solution is 1.00 g/ml.

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  1. 22 June, 11:08
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    Assume you have 1 L of solution.

    Moles F - = M F - x L F - = (0.0610) (1) = 0.0610 moles F-

    0.0610 moles F - x (19.0 g F-/1mole F-) = 1.159 g F - in 1 L of solution

    1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g of solution

    mass % F - = (g F - / g solution) x 100 = (1.159 / 1000) x 100

    = 0.1159%

    parts per million F - = mg F - / L = 1159 / 1 = 1159 ppm F-
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