Express the concentration of a 0.0610 m aqueous solution of fluoride, f-, in mass percentage and in parts per million. assume the density of the solution is 1.00 g/ml.

Assume you have 1 L of solution.

Moles F - = M F - x L F - = (0.0610) (1) = 0.0610 moles F-

0.0610 moles F - x (19.0 g F-/1mole F-) = 1.159 g F - in 1 L of solution

1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g of solution

mass % F - = (g F - / g solution) x 100 = (1.159 / 1000) x 100

= 0.1159%

parts per million F - = mg F - / L = 1159 / 1 = 1159 ppm F-