What is the volume occupied by 6.56 kg of Al?

Answer is: volume occupied by 6.56 kg of Al is 2430 dm ³.

The density of aluminum is 2,7 kg/m³.

m (Al) = 6,56 kg.

V (Al) = m (Al) : d (Al).

V (Al) = 6,56 kg : 2,7 kg/m³.

V (Al) = 2,43 m³ = 2,43 · 1000 = 2430 dm³.

d (Al) - density of aluminium.

V (Al) - volume of aluminium.

If we are given the mass, the volume that the certain substance occupies is calculated by using the density in the equation,

V = m/D

where V is the volume, mi s the mass, and D is density. From the reliable sources, the value of the density of the substance is equal to 2,700 kg/m³.

Substituting the known values from to the equation,

V - (6.56 kg) / (2700 kg/m³)

V = 2.429 x 10^-3 m³

Answer: 2.429 x 10^-3 m³