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29 March, 20:09

How many grams of oxygen is required to react with 9.30 moles of aluminium?

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  1. 29 March, 20:39
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    The grams of O2 required to react with 9.3 0 mole Al is calculated as followsl

    that is 4Al + 3O2 = 2 Al2O3

    from the reacting ratio of Al to O2 which is 4 : 3 the moles of O2 = 9.30 x 3/4 = 6.975 moles

    mass of O2 is therefore = moles x molar mass

    = 6.975 moles x 32g/mol = 223.2 grams
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