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27 October, 04:39

Draw the structure of bromous acid, hbro2. optimize formal charges.

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  1. 27 October, 04:49
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    It would be created like this

    ":" means lone pair of electrons, ignore the "~"

    H---O---Br===O:

    The formal charge would be as follows:

    H: 1-1/2 (2) - 0=0

    O: 6-1/2 (4) - 4=0

    Br: 7-1/2 (6) - 4=0 O: 6-1/2 (4) - 4=0

    Br can hold extra electrons because it can leak those electrons over to the D orbital.
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