Draw the structure of bromous acid, hbro2. optimize formal charges.

It would be created like this

":" means lone pair of electrons, ignore the "~"

H---O---Br===O:

The formal charge would be as follows:

H: 1-1/2 (2) - 0=0

O: 6-1/2 (4) - 4=0

Br: 7-1/2 (6) - 4=0 O: 6-1/2 (4) - 4=0

Br can hold extra electrons because it can leak those electrons over to the D orbital.