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27 October, 03:51

How many molecules are there in 79g of Fe2O3? how many atoms is this?

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  1. 27 October, 04:50
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    There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160 = 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
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