How many ml of 0.250 m h2so4 is required to completely react with 25.0 ml of 1.50 m naoh?

Best Answer: Because the equation is this: MaVa = MbVb

Ma = Molarity of H + ions

Va = Volume of acid solution in mL

Mb = Molarity of OH - ions

Vb = Volume of base solution in mL

Since H2SO4 is a diprotic base (two hydrogens), then one mol of H2SO4 will disassociate into two H + ions

Therefore in the equation you must double the molarity of H2SO4, because the formula doesn't ask for the molarity of the acid, it asks for the molarity of H + ions.

Therefore:

Ma*Va = Mb*Vb

(0.5 M) * Va = (0.25 mL) * (1.5M)

Va = Mb*Vb / Ma

Va = 0.75 mL