Calculate the standard potential, e°, for this reaction from its equilibrium constant at 298 k. 6.47 x 10^5

The working equation for this is written below:

E° = 0.0592logK/n

So, we have to know the value of n first which represents the number of moles electron in the reaction. We cannot answer this because we are not given with the reaction. However, just suppose the reaction is:

Cu⁺ + 2e⁻ - - > Cu

Then, n=2. Continuing,

E° = 0.0592log (6.47*10⁵) / 2 = 0.172 V