Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 * 10-17.

When the salt AgI dissolves in water it dissociates as follows;

AgI - - - > Ag⁺ + I⁻

molar solubility is the number of moles that are dissolved in 1 L of solution.

If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.

the formula for solubility product constant - ksp of AgI is given below

ksp = [Ag⁺][I⁻]

ksp = (x) (x)

ksp = 8.51 x 10⁻¹⁷

therefore,

x² = 8.51 x 10⁻¹⁷

x = 9.22 x 10⁻⁹

since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M