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16 November, 20:04

What is the pH of a 9.50*10-2 M ammonia solution?

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  1. 16 November, 22:51
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    NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

    c=9,50*10⁻² mol/L

    Ammonia solution is a weak electrolyte.

    The dissociation constant of ammonium hydroxide is:

    K=1.78*10⁻⁵

    [OH⁻]=√ (Kc)

    pH=14-pOH=14+lg[OH]⁻

    pH=14+lg (√ (Kc))

    pH=14+lg (√ (1.78*10⁻⁵*9.50*10⁻²)) = 8.23

    pH=8.23
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