2. The electrolyte in automobile lead storage batteries is a 3.75 M sulfuric acid solution that has a density of 1.230 g/mL. Calculate the mass percent, molality, and mol fraction of the sulfuric acid.

i am so lost dont know how to get the kg of solvent,

Solutions:

1.

Density of solution = (1.23 g / mL) • (1000 mL / 1 L)

= 1230 g solution/L solution.

grams of H2SO4 = (3.75 mols H2SO4) • (98.07 g H2SO4 / 1 mol)

= 368 g H2SO4 in 1 L.

mass percentage H2SO4 = 368 g H2SO4 / 1230 g solution) • 100

= 29.9% H2SO4

2. Convert Grams to moles

= 368 g H2SO4 • (1 mol H2SO4 / 98.07 g H2SO4)

= 3.75 mol H2SO4

difference of total solution - total grams = 1230 g solution - 368 g H2SO4

= 862 g H2O.

Convert grams to kg,

= 862 g 8 (1 kg / 1000 g)

= 0.862 kg H2O

Thus,

Molality = m

= 3.75 mol H2SO4 /.862 kg H2O

= 4.35.

3. = 862 g water • (1 mole / 18 g water)

= 47.89 mol water

mole fraction of H2SO4 = X

= 3.75 mol H2SO4 / (3.75 moles H2SO4 + 47.89 moles water)

= 0.726