An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to - 5°C. Assume that there is no volume change in the tire. How does the tire pressure change in response to the temperature change?

1) it decreases

2) 2.65 atm

The tire pressure drops to 2.65 atm.

Step-by-step explanation:

Volume remains constant, so we can use Gay-Lussac's Law.

p₁/T₁ = p₂/T₂ Multiply both sides by T₂

p₂ = p₁ * T₂/T₁

dа ta:

p₁ = 3.00 atm; T₁ = 30.0 °C

p₂ = ?; T₂ = - 5 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = 30.0 + 273.15 = 303.15 K

T₂ = - 5 + 273.15 = 268.15 K

(b) Calculate the new pressure

p₂ = 3.00 * 268.15/303.15

p₂ = 3.00 * 0.8845

p₂ = 2.65 atm

The pressure drops to 2.65 atm.