Calculate the molarity of a solution made by adding 45.4 g of nano3 to a flask and dissolving it with water to create a total volume of 2.50 l.

molarity is defined as the number of moles of solute in 1 L of solution.

molar mass of NaNO ₃ = 85 g/mol

number of moles of NaNO ₃ = 45.4 g / 85 g/mol = 0.534 mol

there are 0.534 mol in 2.50 L solution

therefore number of NaNO ₃ moles in 1 L solution = 0.534 mol / 2.50 L = 0.214 M

molarity of solution is 0.214 M