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9 September, 09:25

Consider this reaction. What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP? 1860 mL 2880 mL 3710 mL 45,100 mL

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  1. 9 September, 10:14
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    Step 1: find number of moles of Mg (divide 4.03 by its molor mass)

    step 2:find number of moles in O2

    step 3: remember STP is 22.4 L = 1 mole

    step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L

    answer is 1860 mL
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