Calculate the molar solubility of baso4 in water, ksp=1.0*10^-10

When BaSO₄ dissolves in water it dissociates as follows;

BaSO₄ - - - > Ba²⁺ + SO₄²⁻

molar solubility of compound is the amount of moles that can be dissolved in 1 L solution

if molar solubility of BaSO₄ is x then molar solubility of Ba²⁺ is x and SO₄²⁻ is x.

the formula for solubility product constant - ksp is as follows

ksp = [Ba²⁺][SO₄²⁻]

ksp = (x) (x)

ksp = x²

and ksp = 1 x 10⁻¹⁰

therefore

x² = 1 x 10⁻¹⁰

x = 1 x 10⁻⁵ M

the molar solubility of BaSO₄ is 1 x 10⁻⁵ M