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24 December, 18:18

If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50 M what is the volume of the new solution

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  1. 24 December, 20:51
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    The volume of the new solution is calculated using the formula below

    M1V1 = M2V2

    M1 = 15.0 M

    V1 = 50.0 ml

    M2=2.50 M

    V2=?

    V2=M1V1/V2

    =50 ml x 15m/2.5 M = 300 ML
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