Ask Question
21 August, 00:56

calculate the final temperature of 202 mL of water initially at 32 degrees celsius upon absorption of 19 kJ of heat

+2
Answers (1)
  1. 21 August, 04:00
    0
    The Final Temperature of water = 54.48°C.

    Explanation:

    Given,

    Volume of water = 202 mL.

    Initial Temperature T₁ = 32°C

    Heat energy absorbed = 19 kJ = 19000 Joules

    Final Temperature T₂ = ?

    Final temperature can be calculated using the formula,

    Q = (mass) (ΔT) (Cp)

    Here ΔT = T₂ - T₁

    Cp = specific heat of water = 4.184 J/g°C.

    For finding the mass, we use the formula,

    Density = Mass/Volume

    Since, Density of water = 1 g/mL.

    Mass of water = 202 grams.

    Now Substituting all values in the formula Q = (mass) (ΔT) (Cp)

    19000 = (202) (T₂ - T₁) (4.184)

    Solving, we get,

    (T₂ - T₁) = 22.48°C

    Therefore, T₂ = 22.48°C + 32°C = 54.48°C.

    Therefore, Final Temperature of water = 54.48°C.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “calculate the final temperature of 202 mL of water initially at 32 degrees celsius upon absorption of 19 kJ of heat ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers