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16 June, 09:40

According to the reaction Cl2O7 + H2O → 2HClO4, how many grams of Cl2O7 must react with an excess of H2O to form 56.2 g HClO4?

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  1. 16 June, 11:25
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    51.17g of Cl2O7

    Explanation:

    The equation for the reaction is given below:

    Cl2O7 + H2O → 2HClO4

    First, let us calculate the masses of Cl2O7 and HClO4 from the balanced equation. This is illustrated below:

    Molar Mass of Cl2O7 = (2x35.5) + (16x7) = 71 + 112 = 183g/mol

    Molar Mass of HClO4 = 1 + 35.5 + (16x4) = 1 + 35.5 + 64 = 100.5g/mol

    Mass of HClO4 from the balanced equation = 2 x 100.5 = 201g

    Now, we can obtain the mass of Cl2O7 that must react to form 56.2g HClO4. This is illustrated below:

    From the equation above,

    183g of Cl2O7 reacted to produced 201g of HClO4.

    Therefore, Xg of Cl2O7 will react to produce 56.2g of HClO4 i. e

    Xg of Cl2O7 = (183 x 56.2) / 201

    Xg of Cl2O7 = 51.17g

    From the calculations made above, 51.17g of Cl2O7 is required to produce 56.2g of HClO4
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