A gas cylinder contains 2.50X103g of O2 (g) in

a volume of 10.0L. What pressure is exerted by the Oxygen at20.0

oC?

188 atm

Explanation:

Given data

Mass of O₂ (m) : 2.50 * 10³ g Volume (V) : 10.0 L Temperature (T) : 20.0°C + 273.15 = 293.2 K

The molar mass of O₂ is 32.00 g/mol. The moles of O₂ are:

2.50 * 10³ g * (1 mol / 32.00 g) = 78.1 mol

We can find the pressure exerted by the oxygen using the ideal gas equation.

P * V = n * R * T

P = n * R * T / V

P = 78.1 mol * (0.0821 atm. L/mol. K) * 293.2 K / 10.0 L

P = 188 atm