Ask Question
26 June, 11:55

A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

a.

Calculate the number of moles of C12H22O11 contained in the sample and record in Table 1. Show your work.

b.

Calculate the moles of each element in C12H22O11 and record in Table

1. Show your work.

c.

Calculate the number of atoms of each type in C12H22O11 and record in

Table 1. Show your work.

+5
Answers (1)
  1. 26 June, 14:41
    0
    a) 0.003512 moles

    b) Moles C = 0.04214 moles carbon

    Moles H = 0.07726 moles hydrogen

    Moles O = 0.03863 moles of oxygen

    c) C atoms = 2.54 * 10^22 carbon atoms

    H atoms = 4.65 * 10^22 hydrogen atoms

    O atoms = 2.33 * 10^22 oxygen atom

    Explanation:

    Step 1: Data given

    Mass of sucrose = 1.202 grams

    Molar mass of sucrose = 342.3 g/mol

    Step 2: Calculate moles of sucrose

    Moles sucrose = Mass sucrose / molar mass sucrose

    Moles sucrose = 1.202 grams / 342.3 g/mol

    Moles sucrose = 0.003512 moles

    Step 3: Calculate moles of each element

    For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

    Moles C: 12*0.003512 = 0.04214 moles carbon

    Moles H: 22 * 0.003512 = 0.07726 moles hydrogen

    Moles O: 11 * 0.003512 = 0.03863 moles of oxygen

    Step 4: Calculate the number of atoms

    C atoms = 6.022 * 10^23 / mol * 0.04214 moles = 2.54 * 10^22 atoms carbon

    H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 * 10^22 atoms H

    O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 * 10^22 atoms O

    0.003512 moles of sucrose containse 6.022 * 10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g. a. Calculate the number of moles of C12H22O11 contained in the sample ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers