How do i balance this

Na + Cl² = NaCl

Balancing equation

Explanation:

In the given reaction, sodium is reacting with chlorine to produce sodium chloride

The chemical equation involved is

Na+Cl_2/rightarrow NaClNa+Cl2→NaCl

When the number of atoms for the reactant side is calculated it gives:

Na = 1

Cl = 2

When the number of atoms for the product side is calculated it gives:

Na = 1

Cl = 1

The obtained result indicates that the Chlorine atom is not equal on both sides. Thus the reaction is not balanced.

The balanced reaction has the number of atoms involved in reaction in reactants as well as the product is equal.

To make both side equal some changes must be made as shown in the balanced equation is

2Na+Cl_2/rightarrow 2NaCl2Na+Cl2→2NaCl

For the above equation, the number of atoms in the reactants is:

Na = 2

Cl = 2

The number of atoms in products is:

Na = 2

Cl = 2

As the number of atoms in the reactants side is equal to the number of atoms in the product side, the reaction is balanced.

You have to have the same number of each element on left as on the right. You have 2Cl on the left, so you must also have two on the right. When adding numbers to make the equation balanced you can only insert coefficients (numbers that are in front of the the element), not subscripts (the ones that float above). So add a coefficient of 2 to the right so that you have 2Cl. Notice there is no sign between the Na and CL on the right. So when adding the coefficient it goes in front of both of them, looking like 2NaCl. I have 2CL on the right and on the left. Adding the two to the right made there be 2 Na, add 2 to the left to make two Na. It looks like: 2Na + Cl^2 = 2NaCl. You know you're done because it's balanced, meaning there's the same number of each on both sides of the equation.