A party balloon was inside a store where the temperature was 27 °C. It had a volume of 2.3 L. The balloon was

taken out of the store, where the temperature outside is - 3 °C. What is the volume of the balloon now?

2.07L

Explanation:

Data obtained from the question include:

T1 (initial temperature) = 27 °C = 27 + 273 = 300K

V1 (initial volume) = 2.3 L

T2 (final temperature) = - 3 °C = - 3 + 273 = 270K

V2 (final volume) = ?

Using V1/T1 = V2/T2, the final volume of the balloon can be obtained as follow:

V1/T1 = V2/T2

2.3/300 = V2/270

Cross multiply to express in linear form.

300 x V2 = 2.3 x 270

Divide both side by 300

V2 = (2.3 x 270) / 300

V2 = 2.07L

Therefore, the new volume of the balloon is 2.07L