How many moles of Ca (No3) 2 are dissolved in 4.55 kg of water in a 0.68 m solution

3.094 moles of Ca (No3) 2 are dissolved in 4.55 kg of water in a 0.68 m solution

Explanation:

1 Kg=1 L for pure water at 4 degrees. So assuming the solvent as pure water, the volume of solution is 4.55 Kg.

Molarity of the solution is given as 0.68

From the formula:

C=n/V (C concentration of solution) and V (volume of the solution)

n = C*V

= 0.68*4.55

= 3.094

3.904 of solute is dissolved to make 4.55 liters of solution to obtain a 0.68 m solution