2. Answer the following questions about a sample of calcium phosphate:

a. What is the molecular weight of Ca3 (PO4) 2?

b. How many moles of Ca3 (PO4) 2are in 1350g?

c. How many molecules of Ca3 (PO4) 2 are there in 1350g?

d. How many phosphorus atoms are there in 1350g of Ca3 (PO4) 2?

e. How many moles of calcium are there in 1350 g of Ca3 (PO4) 2?

f. What is the mass of 2.1 x 1025molecules of Ca3 (PO4) 2?

a) 310.18 g/mol

b) 4.352 moles Ca3 (PO4) 2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e) 13.056 moles Ca

f) 10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3 (PO4) 2

Molecular weight of Ca3 (PO4) 2 = 3*atomic mass of Ca + 2 * atomic mass of P and 8 * atomic mass of O

Molecular weight of Ca3 (PO4) 2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3 (PO4) 2 in 1350 grams

Moles Ca3 (PO4) 2 = mass Ca3 (PO4) 2 / molar mass

Moles Ca3 (PO4) 2 = 1350 grams / 310.18 g/mol

Moles Ca3 (PO4) 2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 * 10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3 (PO4) 2 we need 2 moles P

For 4.352 moles Ca3 (PO4) 2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3 (PO4) 2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3 (PO4) 2

Moles Ca3 (PO4) 2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3 (PO4) 2 = 34.9 moles

Mass Ca3 (PO4) 2 = 34.9 moles * 310.18 g/mol

Mass Ca3 (PO4) 2 = 10825.3 grams