What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?

The answer to your question is pH = 2.2

Explanation:

Data

pH = ?

moles of HCl = 0.927

volume = 150 l

Process

1. - Calculate the Molar concentration of HCl

Molarity = moles / volume (L)

Molarity = 0.927 / 150

= 0.00618

2. - Calculate the pH

pH = - log [HCl]

Substitution

pH = - log [0.00618]

Result

pH = 2.2