The mass of a compound is taken 5 times with the following results: 26.6mg, 26.3mg, 26.2mg, 26.4mg, and 26.1mg. If the true mass is 25.6mg, what is the percent relative error for this set of data? Round to the nearest hundredth of a percent.

2.813%

Explanation:

First we must take the average of the five mass measurements

Average value = sum of all five trials / 5 = 26.6 + 26.3 + 26.2 + 26.4 + 26.1 / 3 = 26.32mg

Now, we have been provided the accurate mass of the compound in the question as 25.6mg

Remember that relative percent error = Average value of measurement - True value of measurement / true value*100

Hence we have;

Percent error=

26.32 - 25.6/25.6 * 100

Percent error = 2.813%