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2 June, 08:07

13. A sample of liquid water at 30.0 C is cooled to - 5.0 C,

13d. How much energy is in the system if you begin with 32.6 g of liquid water?

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  1. 2 June, 08:58
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    Q = 4389 j

    Explanation:

    Given dа ta:

    Initial temperature = 30°C

    Final temperature = - 5.0 °C

    Mass of water = 32.6 g

    Energy in system = ?

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Q = m. c. ΔT

    ΔT = T2 - T1

    ΔT = -5°C - 30°C

    ΔT = 35°C

    Q = m. c. ΔT

    Q = 30.0 g. 4.18 j/g.°C. 35°C

    Q = 4389 j
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