Exactly 5000 mL of air at 223K is warmed and has a new volume of 8.36 liters. What is the new temperature?

100 K

373 K

273 K

123 K

The new temperature is 373 K

Explanation:

Step 1: Data given

Volume air = 5000 mL = 5.0 L

Temperature = 223K

New volume = 8.36 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒V1 = the initial volume = 5.0 L

⇒T1 = the initial temperature = 223 K

⇒V2 = the new volume = 8.36 L

⇒T2 = the new temperature

5.0/223 = 8.36 / T2

T2 = 373 K

The new temperature is 373 K