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6 May, 12:16

If 112 g fr combines with 48 g of O2 how much fe2O3 is formed

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  1. 6 May, 13:10
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    160 g.

    Explanation:

    The balanced equation is

    4Fe + 3O2 - --> 2Fe2O3.

    4 * 56 g of Fe reacts with 6 * 16 g of O2 to give 2 * 160 g Fe2O3.

    224 g Fe reacts with 96g of O2 to give 320 g Fe2O3.

    So 48 g O2 + 224 g Fe produces 320 * 1/2 = 160 g Fe2O3.
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