Ask Question
2 March, 04:51

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 7.50 g of sodium carbonate is mixed with one containing 6.75 g of silver nitrate. After the reaction is complete, the solutions are evaporated to dryness, leaving a mixture of salts. How many grams of each of the following compounds are present after the reaction is complete?

+1
Answers (1)
  1. 2 March, 05:53
    0
    After the reaction we have 5.46 grams of Ag2CO3, 3.37 grams of NaNO3 and remain 5.40 grams of Na2CO3

    Explanation:

    Step 1: Data given

    A solution containing 7.50 g of sodium carbonate is mixed with one containing 6.75 g of silver nitrate.

    Step 2: The balanced equation

    Na2CO3 + 2 AgNO3 → Ag2CO3 + 2 NaNO3

    Step 3: Calculate moles

    Moles = mass / molar mass

    moles Na2CO3 = 7.50 g/105.99 g/mol=0.0708 moles

    moles AgNO3 = 6.75 g / 169.87 g/mol = 0.0397 moles (limiting reactant)

    Step 4: Calculate limiting reactant

    For 1 mol Na2CO3 we need 2 moles AgNO3 to produce 1 mol Ag2CO3 and 2 moles NaNO3

    AgNO3 is the limiting reactatn. It will completely be consumed. (0.0397 moles). Na2CO3 is in excess. There will react 0.0397/2 = 0.01985 moles

    There will remain 0.0708 - 0.01985 = 0.05095 moles Na2CO3

    This is 0.05095 moles * 105.99 g/mol = 5.40 grams

    Step 5: Calculate moles products

    For 1 mol Na2CO3 we need 2 moles AgNO3 to produce 1 mol Ag2CO3 and 2 moles NaNO3

    For 0.0397 moles AgNO3 we'll have 0.0397 moles NaNO3 and 0.01985 moles Ag2CO3

    Step 6: Calculate mass

    Mass Ag2CO3 = moles Ag2CO3 * molar mass

    Mass Ag2CO3 = 0.01985 moles * 275.75 g/mol

    Mass Ag2CO3 = 5.46 grams

    Mass NaNO3 = 0.0397 moles * 84.99 g/mol

    Mass NaNO3 = 3.37 grams

    After the reaction we have 5.46 grams of Ag2CO3, 3.37 grams of NaNO3 and remain 5.40 grams of Na2CO3

    7.50 + 6.75 grams = 14.25

    Mass products = 5.46 + 3.37 grams = 8.83

    mass of reactants in excess = 5.40 grams

    remaining products = 8.83 + 5.40 = 14.23 grams
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers