How many grams of beryllium chloride (BeCl2) are needed to make 7.7 L of a 0.69 M solution?

Question

Chemistry

Zayne Maddox

27 October, 14:46

How many grams of beryllium chloride (BeCl2) are needed to make 7.7 L of a 0.69 M solution?

+1

Answers (1)

Know the Answer?

Owen Beck · Answer 1

419.5 g BeCl2

Explanation:

M = mol solute / L solution

mol solute = M * L solution

mol solute = (0.69 M) * (7.7 L)

mol solute=5.31 mol BeCl2

1 mol BeCl2 - > 79 g

5.31 mol BeCl2 - > x x = 419.5 g BeCl2