What mass of potassium would react with excess chlorine to produce 156 G of potassium chloride

81.66g

Explanation:

First, let us write the balanced equation for the reaction. This is illustrated below:

2K + Cl2 - > 2KCl

Molar Mass of K = 39g/mol

Mass of K from the balanced equation = 2 x 39 = 78g

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

From the equation,

78g of K produced 149g of KCl.

Therefore, Xg of K will produce 156g of KCl i. e

Xg of K = (78 x 156) / 149 = 81.66g