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4 May, 04:42

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (2005 K)

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  1. 4 May, 06:12
    0
    205K

    Explanation:

    The following were obtained from the question:

    n = 4moles

    P = 5.6atm

    V = 12L

    R = 0.082atm. L/Kmol

    T = ?

    PV = nRT

    T = PV/nR

    T = (5.6 x 12) / (4 x 0.082)

    T = 205K
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