Describe how you would prepare 2.44 kg of an aqueous solution that is 16.3% KOH by mass.

Describe how you would prepare 2.44 of an aqueous solution that is 16.3% by mass.

0.163 kg KOH. Add 0.163 kg KOH to 2.277 kg water.

2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.84 kg water.

0.163 kg KOH. Add 0.163 kg KOH to 2.603 kg water.

2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.04 kg water.

Request Answer

Add 0.40 kg KOH to 2.04 kg water.

Explanation:

The formula for mass percentage is:

% (w/w) = (mass of solute / mass of solution) * 100

The data are:

mass of solution: 2.44 kg % (w/w) = 16.3

Substitute and solve:

16.3 = (x / 2.44kg) * 100 x = 16.3 * 2.44kg / 100 = 0.39772kg ≈ 0.40kg

Then, you will need to use 0.40kg of KOH and the amount of water needed to complete 2.44 kg of solution:

water = 2.44kg - 0.40kg = 2.04kg

Conclusion

Add 0.40kg of KOH to 2.04 kg of water.