Ask Question
13 September, 01:33

A 900 liter supply of xenon gas is held at 27 °C and 100 kPa. When the temperature is lowered to - 73

C, what pressure must be applied to compress the gas to 200 liters?

+1
Answers (1)
  1. 13 September, 05:08
    0
    300 kPa

    Explanation:

    Concept tested: Gas Laws (Combined gas law)

    Initial pressure, P₁ = 100 kPa

    Initial temperature, T₁ = 27°C

    But, K = °C + 273, therefore, T₁ = 300 K

    Initial volume, V₁ = 900 L

    New temperature, T₂ = - 73°C

    = - 73°C + 273

    = 200 K

    New volume, V₂ = 200 L

    We are required to calculate the new pressure, P₂

    To find the new pressure of the gas, we are going to use the combined gas law; Combined gas law combines both Charles's law and Boyle's law. According to the combined gas law;

    P₁V₁/T₁ = P₂V₂/T₂

    To calculate the new Pressure, P₂, we rearranging the formula;

    P₂ = (P₁V₁T₂) : (V₂T₁)

    Therefore;

    P₂ = (100 kPa * 900 L * 200 K) : (200 L * 300 K)

    = 300 kPa

    Therefore, a pressure of 300 kPa must be applied.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 900 liter supply of xenon gas is held at 27 °C and 100 kPa. When the temperature is lowered to - 73 C, what pressure must be applied to ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers