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18 November, 11:24

Suppose you digested 0.25 g of a copper ore samplein 15 mL of solution. One mL of this solution is transferred to a 10 mL volumetric flask, which is filled to the calibration level. The resulting concentrationwas 0.0087M Cu2+. What is the concentration of copper in the ore sample in units of percentage?

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  1. 18 November, 13:53
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    10 mL = 10⁻² L

    1 mL of solution contains. 0087 x 10⁻² mole of Cu

    15 mL of solution will contain. 1305 x 10⁻² mole of Cu

    .1305 x 10⁻² mole of copper =.1305 x 63.5 x 10⁻² gm of Cu

    =.08286 gm

    concentration of copper in the ore sample

    =.08286 x 100 /.25

    = 33 % approx.
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