2Nal + Cl2 → 2NACI + I2

How many grams of iodine are liberated if 546 g of chlorine react with excess sodium iodide?

(I'm a really busy AP student with a lot of homework. Just need the work and answer!)

Mass of iodine = 1954.26 g

Explanation:

Given dа ta:

Mass of chlorine react = 546 g

Mass of iodine produced = ?

Solution:

Chemical equation:

2NaI + Cl₂ → 2NaCl + I₂

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 546 g/71 g/mol

Number of moles = 7.7 mol

Now we will compare the moles of chlorine with iodine.

Cl₂ : I₂

1 : 1

7.7 : 7.7

Mass of iodine:

Mass = number of moles * molar mass

Mass = 7.7 mol * 253.8 g/mol

Mass = 1954.26 g