Ask Question
27 July, 11:15

The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. Vanadium-50 has an abundance of 0.250% and a mass of 49.947 amu. Vanadium-51 has an abundance of 99.750% and a mass of 50.944 amu. Calculate the average atomic mass of vanadium.

A) 50.942 amu

B) 62.558 amu

C) 63.303 amu

D) 5094.151 amu

+1
Answers (1)
  1. 27 July, 12:25
    0
    The answer to your question is letter A

    Explanation:

    Abundance Atomic mass

    V-50 0.25% 49.947

    V-51 99.750% 50.944

    Formula

    Average atomic mass = [V-50-Abundance x V-50-Atomic mass] +

    [ V-51-Abundance x V-51-Atomic mass]

    Substitution

    Average atomic mass = [ 0.0025 x 49.947] + [0.9975 x 50.944]

    = 0.125 + 50.817

    Result

    = 50.942 amu
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. Vanadium-50 has an abundance of 0.250% and a mass of 49.947 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers