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16 April, 08:47

If I have 31 liters of helium in a balloon at 9°C and increase the temperature of the balloon to 28°C, what will the new volume of the balloon be if the pressure remains constant? What is T2?

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  1. 16 April, 10:33
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    Answer: The new volume of the balloon is 33 liters while T2 is 301K

    Explanation:

    Initial volume of helium V1 = 31 liters

    Initial temperature T1 = 9°C

    Convert temperature in Celsius to Kelvin

    (9°C + 273°C = 280K)

    Final temperature T2 = 28°C

    (28°C + 273°C = 301K)

    Final volume V2 = ?

    According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

    Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

    31/280 = V2/301

    To get the value of V2, cross multiply

    V2 = (31 x 301) / 280

    V2 = 9331 / 280

    V2 = 33.325 liters (approximated to 33liters)

    Thus, the new volume of the balloon is 33 liters while T2 is 301K
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