OLLU

What are the number of atoms in 22.4dm of chlorine gas at S. T. P:

A. 10

B. 20

C 6.02 x 1023

- 1.2 x 1024

3

C. 6 E23 atoms Cl2

Explanation:

mol ≡ 6.02 E23 atoms

S. T. P:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

ideal gas:

PV = RTn

∴ R = 0.082 atm. L/K. mol

∴ V = 22.4 dm³ = 22.4 L

⇒ mol (n) = PV/RT

⇒ n Cl2 (g) = ((1 atm) (22.4 L) / (0.082 atm. L/K. mol) (298 K))

⇒ n Cl2 (g) = 0.9166 mol

⇒ atoms Cl2 (g) = (0.9166 mol) * (6.022 E23 atoms/mol)

⇒ atoms Cl2 (g) = 5.52 E23 atoms ≅ 6 E23 atoms