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26 March, 10:50

Based of the chemical reaction below, if you have 3.56x10^23 molecules of C3H8, how many liters of CO2 gas will be produced at STP? C3H8+5) 2-->3CO2+4H2O

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  1. 26 March, 12:29
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    39.65L

    Explanation:

    First, let us calculate the number of mole present in 3.56x10^23 molecules of C3H8.

    1 mole of any substance contains 6.02x10^23 molecules as discovered from Avogadro's hypothesis. This means that 1mole of C3H8 contains 6.02x10^23 molecules.

    Now, if 1mole of C3H8 contains 6.02x10^23 molecules, then Xmol of C3H8 will contain 3.56x10^23 molecules i. e

    Xmol of C3H8 = 3.56x10^23/6.02x10^23 = 0.59mole

    The equation for the reaction is given below:

    C3H8 + 5O2 - > 3CO2 + 4H2O

    From the equation above,

    1 mole of C3H8 produced 3moles of CO2.

    Therefore, 0.59mole of C3H8 will produce = 0.59 x 3 = 1.77mole of CO2.

    Now let us calculate the volume occupied by 1.77mole of CO2. This is illustrated below:

    1 mole of any gas occupy 22.4L at stp.

    Therefore, 1.77mole of CO2 will occupy = 1.77 x 22.4 = 39.65L

    Therefore, 39.65L of CO2 are produced.
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