Ask Question
24 November, 10:19

A mixture of carbon dioxide and an unknown gas was allowed to effuse from a container. The carbon dioxide took 1.25 times as long to escape as the unknown gas. Which one could be the unknown gas?

+5
Answers (1)
  1. 24 November, 12:55
    0
    CO

    Explanation:

    From Graham's law, time taken to diffuse is directly proportional to the molecular mass of the gases. For two different gases.

    t1/t2=√m1/m2

    Since gas 1 diffuse 1.25 times as slowly as gas 2 and gas 1 is CO2 with m as 44g

    1.25/1=√44/m2

    Therefore m2=28g CO
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A mixture of carbon dioxide and an unknown gas was allowed to effuse from a container. The carbon dioxide took 1.25 times as long to escape ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers