Ask Question
9 July, 19:02

The combustion of 1.00 mol of glucose, C6H12O6, releases 2820 kJ of heat. If 2.0 g of glucose is burned in a calorimeter containing 1.0 kg of water, and the temperature increases by 3.5 oC, what is the heat capacity of the calorimeter?

+4
Answers (1)
  1. 9 July, 21:50
    0
    The heat capacity of the calorimeter is 4.76 kJ/°C

    Explanation:

    Step 1: Data given

    1.00 mol of glucose releases 2820 kJ of heat

    Mass of glucose = 2.0 grams

    Mass of water = 1000 grams

    The temperature increases with 3.5 °C

    Step 2: Calculate moles

    moles glucose = mass glucose / molar mass glucose

    moles glucose = 2.0 grams / 180.16 g/mol

    moles glucose = 0.0111 moles

    Step 3: Calculate heat produced by the combustion

    Heat produced = 2820 kJ/mol * 0.0111 moles

    Heat produced = 31.302 kJ = 31302 J

    Step 4: Calculate heat absorbed by the water

    Q = m*c*ΔT

    ⇒ with m = the mass of water = 1000 grams

    ⇒ with c = the specific heat of water = 4.184 J/g°C

    ⇒ with ΔT = The change in temperature = 3.5 °C

    Q = 1000 * 4.184 * 3.5

    Q = 14644 J absorbed by the water

    Step 5: Calculate heat basorbed by the calorimeter

    Q = 31302 - 14644 = 16658 J absorbed by the calorimeter

    Step 6: Calculate the heat capacity of the calorimeter

    c = 16658 J / 3.5 °C

    c = 4759 J/°C = 4.76 kJ/°C

    The heat capacity of the calorimeter is 4.76 kJ/°C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The combustion of 1.00 mol of glucose, C6H12O6, releases 2820 kJ of heat. If 2.0 g of glucose is burned in a calorimeter containing 1.0 kg ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers