a sample of carbon monoxide gas occupies 150.0mL at 25.0 degrees Celsius. It is then cooled at a constant pressure until it occupies 100.0mL. What is the new temperature in degrees Celsius?

T₂ = 16.7 °C

Explanation:

Given dа ta:

Initial volume = 150.0 mL

Temperature = 25.0 °C

Final volume = 100 mL

Final temperature = ?

Solution:

V₁ / T₁ = V₂/T₂

T₂ = V₂. T₁/V₁

T₂ = 100 mL. 25 °C / 150.0 mL

T₂ = 2500 mL. °C / 150.0 mL

T₂ = 16.7 °C